The ionisation energy of an electron in the ground state of helium atom is 24.6 eV. The energy required to remove both the electron is

Question

The ionisation energy of an electron in the ground state of helium atom is 24.6 eV. The energy required to remove both the electron is (A) 51.8 eV (B) 79 eV (C) 38.2 eV (D) 49.2 eV

Tardigrade Admin · Accepted Answer

lonisation energy in ground state =24.6 eV Energy required to remove 2n electron from He 2+ =Z2(13.6) eV =(2)2(13.6)=54.4 eV So, total energy required =24.6+54.4=79 eV

Q. The ionisation energy of an electron in the ground state of helium atom is $24.6 e V$ . The energy required to remove both the electron is

51.8 eV

79 eV

38.2 eV

49.2 eV

lonisation energy in ground state $= 24.6 e V$
Energy required to remove $2^{n}$ electron from $H e^{2 +}$
$= Z^{2} (13.6) e V = (2)^{2} (13.6) = 54.4 e V$
So, total energy required $= 24.6 + 54.4 = 79 e V$

Q. The ionisation energy of an electron in the ground state of helium atom is 24.6eV. The energy required to remove both the electron is