Question

The ionic product of water at $25^{\circ }C$ is $10^{-14}$. Its ionic product at $90^{\circ }C$ will be,

• A. $1\times 10^{-14}$
• B. $1\times 10^{-16}$
• C. $1\times 10^{-20}$
• D. $1\times 10^{-12}$

Answer 1

Answer: (D)

as temperature increases Ionic product increases.