The instantaneous voltage of a 50 Hz generator giving peak voltage as 300 V. The generator equation for this voltage is

Question

The instantaneous voltage of a 50 Hz generator giving peak voltage as 300 V. The generator equation for this voltage is (A) V = 50 sin 300π t (B) V = 300 sin 100π t (C) V = 6 sin 100π t (D) V = 50 sin 100π t

Tardigrade Admin · Accepted Answer

Here, frequency of generator, v = 50 Hz peak voltage, V0 = 300 V Instantaneous voltage of the generator, V = V0 sin ω t = V0 sin 2π vt = 300 sin 100 π t

Q. The instantaneous voltage of a $50 Hz$ generator giving peak voltage as $300 V$ . The generator equation for this voltage is

$V = 50 sin 300 π t$

$V = 300 sin 100 π t$

$V = 6 sin 100 π t$

$V = 50 sin 100 π t$

Here, frequency of generator, $v = 50 Hz$
peak voltage, $V_{0} = 300 V$
Instantaneous voltage of the generator, $V = V_{0} sin ω t = V_{0} sin 2 π v t = 300 sin 100 π t$

Q. The instantaneous voltage of a 50Hz generator giving peak voltage as 300V. The generator equation for this voltage is

V=50sin300πt

V=300sin100πt

V=6sin100πt

V=50sin100πt