The increase in electrostatic potential energy of a dipole of moment p when it is taken from parallel to anti-parallel orientation in an electric field E is

Question

The increase in electrostatic potential energy of a dipole of moment p when it is taken from parallel to anti-parallel orientation in an electric field E is (A) 2pE (B) 3pE (C) 5pE (D) 6pE

Tardigrade Admin · Accepted Answer

p = dipole moment U = - pEcosθ U1 =-pEcos0° U2 =-pEcos180° Δ U =(U2-U1)=pE +pE=2 pE Increase in potential energy Δ U =2 pE

Q. The increase in electrostatic potential energy of a dipole of moment p when it is taken from parallel to anti-parallel orientation in an electric field E is

2pE

3pE

5pE

6pE

p = dipole moment
U = - pEcos $θ$
$U_{1} = - pE cos 0^{\circ}$
$U_{2} = - pE cos 18 0^{\circ}$
$Δ U = (U_{2} - U_{1}) = pE + pE = 2 pE$
Increase in potential energy $Δ U = 2 pE$

Q. The increase in electrostatic potential energy of a dipole of moment p when it is taken from parallel to anti-parallel orientation in an electric field E is

2pE

3pE

5pE

6pE

p = dipole moment U = - pEcosθ U1​=−pEcos0∘ U2​=−pEcos180∘ ΔU=(U2​−U1​)=pE+pE=2pE Increase in potential energy ΔU=2pE

p = dipole moment
U = - pEcos $θ$
$U_{1} = - pE cos 0^{\circ}$
$U_{2} = - pE cos 18 0^{\circ}$
$Δ U = (U_{2} - U_{1}) = pE + pE = 2 pE$
Increase in potential energy $Δ U = 2 pE$