Question

The incorrect statement regarding ${}^{\prime }{X}^{\prime }$ in given reaction is :

$B{F}_3+LiAl{H}_4\stackrel{Ether}{\to }\left(X\right)+LiF+Al{F}_3$

• A. Twelve electrons are involved in bonding
• B. Four, two centre-two electron bonds
• C. Two, three centre-two electron bonds
• D. $X$ does not react with $N{H}_3$

Answer 1

Answer: (D)

Here X is $B_2{H}_6$ and statement A, B and C are correct. only D is incorrect as it can react with ammonia

$$\begin{gathered} B{F}_3+LiAl{H}_4\stackrel{Ether}{\to }{B}_2{H}_6 \\ (X)+LiF+Al{F}_3 \end{gathered}$$

$N{H}_3$ can react with $B_2{H}_6$

$B_2{H}_6+2N{H}_3\stackrel{warm}{\to }[B{H}_2.2N{H}_3{]}^{+}.[B{H}_4{]}^{-}\stackrel{200^{\circ }C}{\to }{B}_3{N}_3{H}_6$ (Inorganic benzene)