The hydrolysis of sodium carbonate involves the reaction between

Question

The hydrolysis of sodium carbonate involves the reaction between (A) sodium ion and water (B)  Na+ and OH-  (C)  CO32- and water (D)  CO32- and H+

Tardigrade Admin · Accepted Answer

Na 2 CO 3+2 H 2 O leftharpoons 2 NaOH + H 2 CO 3 or 2 Na + + CO 32-+2 H 2 O leftharpoons 2 Na ++2 OH -+ H 2 CO 3 or CO 32-+2 H 2 O leftharpoons 2 OH -+ H 2 CO 3 It is anionic hydrolysis.

Q. The hydrolysis of sodium carbonate involves the reaction between

sodium ion and water

$N a^{+}$ and $O H^{-}$

$C O_{3}^{2 -}$ and water

$C O_{3}^{2 -}$ and $H^{+}$

$N a_{2} C O_{3} + 2 H_{2} O ⇌ 2 N a O H + H_{2} C O_{3}$

or $2 N a^{+} + C O_{3}^{2 -} + 2 H_{2} O$

$⇌ 2 N a^{+} + 2 O H^{-} + H_{2} C O_{3}$

or $C O_{3}^{2 -} + 2 H_{2} O ⇌ 2 O H^{-} + H_{2} C O_{3}$

It is anionic hydrolysis.

Q. The hydrolysis of sodium carbonate involves the reaction between

sodium ion and water

Na+ and OH−

CO32−​ and water

CO32−​ and H+

Na2​CO3​+2H2​O⇌2NaOH+H2​CO3​ or 2Na++CO32−​+2H2​O ⇌2Na++2OH−+H2​CO3​ or CO32−​+2H2​O⇌2OH−+H2​CO3​ It is anionic hydrolysis.

$N a^{+}$ and $O H^{-}$

$C O_{3}^{2 -}$ and water

$C O_{3}^{2 -}$ and $H^{+}$

$N a_{2} C O_{3} + 2 H_{2} O ⇌ 2 N a O H + H_{2} C O_{3}$

or $2 N a^{+} + C O_{3}^{2 -} + 2 H_{2} O$

$⇌ 2 N a^{+} + 2 O H^{-} + H_{2} C O_{3}$

or $C O_{3}^{2 -} + 2 H_{2} O ⇌ 2 O H^{-} + H_{2} C O_{3}$

It is anionic hydrolysis.