The hydrolysis constant of a salt of weak acid and weak base is inversely proportional to:

Question

The hydrolysis constant of a salt of weak acid and weak base is inversely proportional to: (A) ionic product of water (B) dissociation constant of both weak acid and weak base (C) dissociation constant of weak acid (D) dissociation constant of weak base

Tardigrade Admin · Accepted Answer

Kh=(Kω /Ka× Kb) from this, it is clear that hydrolysis constant of a salt of weak acid and weak base is inversely proportional to dissociation constant of both weak acid and weak base.

Q. The hydrolysis constant of a salt of weak acid and weak base is inversely proportional to:

ionic product of water

dissociation constant of both weak acid and weak base

dissociation constant of weak acid

dissociation constant of weak base

$K_{h} = \frac{K _{ω}}{K _{a} \times K _{b}}$ from this, it is clear that hydrolysis constant of a salt of weak acid and weak base is inversely proportional to dissociation constant of both weak acid and weak base.

Q. The hydrolysis constant of a salt of weak acid and weak base is inversely proportional to:

ionic product of water

dissociation constant of both weak acid and weak base

dissociation constant of weak acid

dissociation constant of weak base

Kh​=Ka​×Kb​Kω​​ from this, it is clear that hydrolysis constant of a salt of weak acid and weak base is inversely proportional to dissociation constant of both weak acid and weak base.

$K_{h} = \frac{K _{ω}}{K _{a} \times K _{b}}$ from this, it is clear that hydrolysis constant of a salt of weak acid and weak base is inversely proportional to dissociation constant of both weak acid and weak base.