The hydrocarbon of molecular mass 72 gives a single monochloride and two dichlorides on photochlorination is

Question

The hydrocarbon of molecular mass 72 gives a single monochloride and two dichlorides on photochlorination is (A) pentane (B) 2-methylbutane (C) 2,2-dimethylpropane (D) none of the above

Tardigrade Admin · Accepted Answer

The hydrocarbon of mass 72 is C5H12 . Since there is one monoclhoro derivative, the compound has twelve equivalent H's in four equivalent CH3′s . The compound is ( CH 3)4 C (2,2-dimethylpropane) and the chloro derivative are as follows <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-b8ky0pkzpryj.png" />

Q. The hydrocarbon of molecular mass 72 gives a single monochloride and two dichlorides on photochlorination is

pentane

2-methylbutane

2,2-dimethylpropane

none of the above

The hydrocarbon of mass 72 is $C_{5} H_{12}$ . Since there is one monoclhoro derivative, the compound has twelve equivalent H's in four equivalent $C H_{3}' s$ . The compound is $(C H_{3})_{4} C$ (2,2-dimethylpropane) and the chloro derivative are as follows

Q. The hydrocarbon of molecular mass 72 gives a single monochloride and two dichlorides on photochlorination is

pentane

2-methylbutane

2,2-dimethylpropane

none of the above

The hydrocarbon of mass 72 is C5​H12​ . Since there is one monoclhoro derivative, the compound has twelve equivalent H's in four equivalent CH3​′s . The compound is (CH3​)4​C (2,2-dimethylpropane) and the chloro derivative are as follows

The hydrocarbon of mass 72 is $C_{5} H_{12}$ . Since there is one monoclhoro derivative, the compound has twelve equivalent H's in four equivalent $C H_{3}' s$ . The compound is $(C H_{3})_{4} C$ (2,2-dimethylpropane) and the chloro derivative are as follows