Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The hybridization of sulphur dioxide is:
Q. The hybridization of sulphur dioxide is:
1789
227
Chemical Bonding and Molecular Structure
Report Error
A
s
p
16%
B
s
p
3
16%
C
s
p
2
61%
D
d
s
p
2
7%
Solution:
S
O
2
H
=
2
1
(
V
+
X
−
C
+
A
)
(
V
→
number of
e
−
s
in valency shell of central atom)
H
=
2
1
(
6
+
0
)
=
3
⇒
S
is
s
p
2
hybridized with
2
b
.
p
.
and
1
l
.
p
.