Question

The hybridisation of atomic orbital of nitrogen in $N{O}_2^{+},N{O}_3^{-}$ and $N{H}_4^{+}$ are respectively

• A. $sp,s{p}^2,s{p}^3$
• B. $s{p}^2,s{p}^3,sp$
• C. $s{p}^2,sp,s{p}^3$
• D. $s{p}^{2}d,s{p}^3,sp$

Answer 1

Answer: (A)

Nitronium ion $(N{O}_2^{+})$

Hybridisation $=sp$
Geometry $=$ linear
Nitrate $(N{O}_3^{-})$

Hybridisation $=s{p}^2$
Geometry $=$ trigonal planar
Ammonium ion $(N{H}_4^{+})$

Hybridisation $=s{p}^3$
Geometry $=$ tetrahedral