Question

The hybrid state of sulphur in $S{O}_4^{2-}$ is:

• A. $s{p}^3$
• B. $s{p}^2$
• C. $sp$
• D. none of these

Answer 1

Answer: (A)

S atom, in $S{O}_4^{2-},$ remains $s{p}^3-$ hybridized.
Hence, hybridisation $=s{p}^3$