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Tardigrade
Question
Chemistry
The heat evolved in the combustion of 112 L of water gas ( CO + H 2. in the ratio of 1: 1 volume ) is (given that heats of combustion of H 2 CO are -241.8 -283 kJ mol -1 respectively). Assume STP condition throughout:
Q. The heat evolved in the combustion of
112
L
of water gas
(
CO
+
H
2
in the ratio of 1 : 1 volume
)
is (given that heats of combustion of
H
2
&
CO
are
−
241.8
&
−
283
k
J
m
o
l
−
1
respectively). Assume STP condition throughout:
1829
226
Thermodynamics
Report Error
A
-1414 kJ
B
-1209 kJ
C
-1312 kJ
D
-524.8 kJ
Solution:
CO
+
2
1
O
2
→
C
O
2
;
Δ
H
=
−
283
k
J
/
m
o
l
H
2
+
2
1
O
2
→
H
2
O
;
Δ
H
=
−
241.8
k
J
/
m
o
l
In the above rxns,
56
L
of
CO
&56
L
of
H
2
reacts (since water gas has
CO
&
H
2
in 1: 1 volume ratio)
At STP,
56
L
of
CO
=
22.4
56
mole of
CO
=
2.5
moles
At STP,
56
L
of
H
2
=
22.4
56
mole of
H
2
=
2.5
moles
Energies released by burning 2.5 moles of
CO
=
2.5
×
283
=
707.5
k
J
Energies released by burning 2.5 mole of
H
2
=
2.5
×
241.8
=
604.5
k
J
Total energy released
=
707.5
+
604.5
=
−
1312
k
J