The heat capacity of a bomb calorimeter is 500 J/oC. When 0.1 g of a methane was burnt in this calorimeter, the temperature rose by 2oC. The value of Δ textE per mole will be

Question

The heat capacity of a bomb calorimeter is 500 J/oC. When 0.1 g of a methane was burnt in this calorimeter, the temperature rose by 2oC. The value of Δ textE per mole will be (A) + text10 kJ (B) - text10 kJ (C) + text160 kJ (D) - text160 kJ

Tardigrade Admin · Accepted Answer

Δ textE = - ( textM/ textw) × textC × Δ textt = - (1 6/ text0.1) × 5 0 0 × 2 = - 1 6 0 × 1 03 textJ = - text160 kJ (minus sign is used as heat is evolved.)

Q. The heat capacity of a bomb calorimeter is 500 J/^oC. When 0.1 g of a methane was burnt in this calorimeter, the temperature rose by 2^oC. The value of $Δ E$ per mole will be

$+ 10 kJ$

$- 10 kJ$

$+ 160 kJ$

$- 160 kJ$

$Δ E = - \frac{M}{w} \times C \times Δ t$

$= - \frac{16}{0.1} \times 500 \times 2 = - 160 \times 1 0^{3} J = - 160 kJ$ (minus sign is used as heat is evolved.)

Q. The heat capacity of a bomb calorimeter is 500 J/oC. When 0.1 g of a methane was burnt in this calorimeter, the temperature rose by 2oC. The value of ΔE per mole will be

+10 kJ

−10 kJ

+160 kJ

−160 kJ