The heart of a man pumps 5 L of blood through the arteries per minute at a pressure of 150 mm of mercury. If the density of mercury be 13.6 × 103 kg m -3 and g=10 ms -2, then the power of heart in watt is

Question

The heart of a man pumps 5 L of blood through the arteries per minute at a pressure of 150 mm of mercury. If the density of mercury be 13.6 × 103 kg m -3 and g=10 ms -2, then the power of heart in watt is (A) 1.70 (B) 2.35 (C) 3.0 (D) 1.50

Tardigrade Admin · Accepted Answer

Given, pressure =150 mm of Hg =0.15 m of Hg ρ=13.6 × 103 kg m -3, g=10 ms -2 h=0.15 m , V=5 × 10-3 m 3 and t=60 s Pumping rate of heart of a man =(d V/d t)=(5 × 10-3/60) m 3 s -1 Power of heart =p ⋅ (d V/d t)=ρ g h ⋅ (d V/d t) (∵ p=ρ g h) =((13.6 × 103 kg m -3)(10) ×(0.15 × 5 × 10-3)/60) =1.70 W

Q. The heart of a man pumps $5 L$ of blood through the arteries per minute at a pressure of $150 mm$ of mercury. If the density of mercury be $13.6 \times 1 0^{3} k g m^{- 3}$ and $g = 10 m s^{- 2}$ , then the power of heart in watt is

$1.70$

$2.35$

$3.0$

$1.50$

Q. The heart of a man pumps 5L of blood through the arteries per minute at a pressure of 150mm of mercury. If the density of mercury be 13.6×103kgm−3 and g=10ms−2, then the power of heart in watt is

1.70

2.35

3.0

1.50

Given, pressure =150mm of Hg=0.15m of Hg ρ=13.6×103kgm−3,g=10ms−2 h=0.15m,V=5×10−3m3 and t=60s Pumping rate of heart of a man =dtdV​=605×10−3​m3s−1 Power of heart =p⋅dtdV​=ρgh⋅dtdV​(∵p=ρgh) =60(13.6×103kgm−3)(10)×(0.15×5×10−3)​ =1.70W

Q. The heart of a man pumps $5 L$ of blood through the arteries per minute at a pressure of $150 mm$ of mercury. If the density of mercury be $13.6 \times 1 0^{3} k g m^{- 3}$ and $g = 10 m s^{- 2}$ , then the power of heart in watt is

$1.70$

$2.35$

$3.0$

$1.50$