The hardness of a water sample containing 10-3 M MgSO4 expressed as CaCO3 equivalents (in ppm) is. (molar mass of MgSO4 is 120.37 g/mol) Given --

Question

The hardness of a water sample containing 10-3 M MgSO4 expressed as CaCO3 equivalents (in ppm) is. (molar mass of MgSO4 is 120.37 g/mol) Given -- (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

10-3 molar MgSO 4=10-3 moles of MgSO 4 present in 1 Litre. n CaCO 3= n MgSO 4 PPM (. in term of .CaCO 3)=(10-3 × 100/1000) × 106 =100 ppm

Q. The hardness of a water sample containing $1 0^{- 3}$ M $M g S O_{4}$ expressed as $C a C O_{3}$ equivalents (in ppm) is__________.
(molar mass of $M g S O_{4}$ is 120.37 g/mol)
Given --

$1 0^{- 3}$ molar $M g S O_{4} = 1 0^{- 3}$ moles of $M g S O_{4}$ present in 1 Litre.
$n_{C a C O_{3}} = n_{M g S O_{4}}$
$PPM ($ in term of $C a C O_{3}) = \frac{1 0 ^{- 3} \times 100}{1000} \times 1 0^{6}$
$= 100 pp m$

Q. The hardness of a water sample containing 10−3 M MgSO4​ expressed as CaCO3​ equivalents (in ppm) is__________. (molar mass of MgSO4​ is 120.37 g/mol) Given --

10−3 molar MgSO4​=10−3 moles of MgSO4​ present in 1 Litre. nCaCO3​​=nMgSO4​​ PPM( in term of CaCO3​)=100010−3×100​×106 =100ppm

Q. The hardness of a water sample containing $1 0^{- 3}$ M $M g S O_{4}$ expressed as $C a C O_{3}$ equivalents (in ppm) is__________.
(molar mass of $M g S O_{4}$ is 120.37 g/mol)
Given --

$1 0^{- 3}$ molar $M g S O_{4} = 1 0^{- 3}$ moles of $M g S O_{4}$ present in 1 Litre.
$n_{C a C O_{3}} = n_{M g S O_{4}}$
$PPM ($ in term of $C a C O_{3}) = \frac{1 0 ^{- 3} \times 100}{1000} \times 1 0^{6}$
$= 100 pp m$