The half life period of a first order chemical reaction is 6.93 minutes. The time required for the completion of 99 % of the chemical reaction will be ( log 2 = 0.301)

Question

The half life period of a first order chemical reaction is 6.93 minutes. The time required for the completion of 99 % of the chemical reaction will be ( log 2 = 0.301) (A) 23.03 minutes (B) 46.06minutes (C) 460.6 minutes (D) 230.03 minutes

Tardigrade Admin · Accepted Answer

K =(0.693/ t (1)2) K =(0.693/6.93)=10-1 min -1 10-1=(2.303/ t ) log (100/1) t =(2.303 × 2/10-1)=46.06 min

Q. The half life period of a first order chemical reaction is $6.93$ minutes. The time required for the completion of $99%$ of the chemical reaction will be $(lo g 2 = 0.301)$

23.03 minutes

46.06minutes

460.6 minutes

230.03 minutes

$K = \frac{0.693}{t _{\frac{1}{2}}}$
$K = \frac{0.693}{6.93} = 1 0^{- 1} min^{- 1}$
$1 0^{- 1} = \frac{2.303}{t} lo g \frac{100}{1}$
$t = \frac{2.303 \times 2}{1 0 ^{- 1}} = 46.06 min$

Q. The half life period of a first order chemical reaction is 6.93 minutes. The time required for the completion of 99% of the chemical reaction will be (log2=0.301)