The half-life of a radioactive isotope is three hours. If the initial mass of the isotope were 256 g, the mass of it in grams remaining undecayed after 18 hours would be:

Question

The half-life of a radioactive isotope is three hours. If the initial mass of the isotope were 256 g, the mass of it in grams remaining undecayed after 18 hours would be: (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

t1 / 2= text3 hours, n= textT/t1 / 2=18/3=6 textN = ( textN)0 ((1/2))6 = 2 5 6 × (1/8) × (1/8) = text4 textg ⋅

Q. The half-life of a radioactive isotope is three hours. If the initial mass of the isotope were $256 g$ , the mass of it in grams remaining undecayed after $18$ hours would be:

$t_{1/2} = 3 hours, n = T / t_{1/2} = 18/3 = 6$
$N = (N)_{0} (\frac{1}{2})^{6}$
$= 256 \times \frac{1}{8} \times \frac{1}{8} = 4 g \cdot$

Q. The half-life of a radioactive isotope is three hours. If the initial mass of the isotope were 256g, the mass of it in grams remaining undecayed after 18 hours would be:

t1/2​=3 hours, n=T/t1/2​=18/3=6 N=(N)0​(21​)6 =256×81​×81​=4g⋅

Q. The half-life of a radioactive isotope is three hours. If the initial mass of the isotope were $256 g$ , the mass of it in grams remaining undecayed after $18$ hours would be:

$t_{1/2} = 3 hours, n = T / t_{1/2} = 18/3 = 6$
$N = (N)_{0} (\frac{1}{2})^{6}$
$= 256 \times \frac{1}{8} \times \frac{1}{8} = 4 g \cdot$