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Tardigrade
Question
Mathematics
The greatest value of (2 sin θ+3 cos θ+4)3 ⋅(6-2 sin θ-3 cos θ)2, as θ ∈ R, is
Q. The greatest value of
(
2
sin
θ
+
3
cos
θ
+
4
)
3
⋅
(
6
−
2
sin
θ
−
3
cos
θ
)
2
, as
θ
∈
R
, is
16
221
Trigonometric Functions
Report Error
A
2345
B
3456
C
1234
D
4567
Solution:
Clearly,
2
sin
θ
+
3
cos
θ
+
4
>
0∀
θ
∈
R
and
6
−
2
sin
θ
−
3
cos
θ
>
0∀
x
∈
R
Put.
2
sin
θ
+
3
cos
θ
+
4
=
x
and
6
−
2
sin
θ
−
3
cos
θ
=
y
Now,
x
+
y
=
10
Also,
A
.
M
≥
G
.
M
. (for positive numbers)
∴
5
3
x
+
3
x
+
3
x
+
2
y
+
2
y
≥
(
27
x
3
⋅
4
y
2
)
5
1
∴
(
2
sin
θ
+
3
cos
θ
+
4
)
3
(
6
−
2
sin
θ
−
3
cos
θ
)
2
≤
(
32
)
(
27
)
(
4
)
=
3456