The graph between √E k and (1/ p ) is ( E k =. kinetic energy and p = momentum) -

Question

The graph between √E k and (1/ p ) is ( E k =. kinetic energy and p = momentum) - (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

E k =( p 2/2 m ) ⇒ √ E K × (1/ p )= constant ∴ graph is rectangular hyperbola

Q. The graph between $E_{k}$ and $\frac{1}{p}$ is $(E_{k} =$ kinetic energy and $p =$ momentum) $-$