The geometry possessed by [Ni(CO)4] is

Question

The geometry possessed by [Ni(CO)4] is (A) tetrahedral (B) square planar (C) linear (D) octahedral

Tardigrade Admin · Accepted Answer

In [Ni(CO)4], oxidation state of Ni = 0 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/199bd39b89953ca5e07f75db976e6219-.png" /> sp3 hybridisation has tetrahedral shape.

Q. The geometry possessed by $[N i (CO)_{4}]$ is

tetrahedral

square planar

linear

octahedral

In $[N i (CO)_{4}]$ , oxidation state of $N i = 0$

$s p^{3}$ hybridisation has tetrahedral shape.

Q. The geometry possessed by [Ni(CO)4​] is