Question

The geometry of the compound $[Pt(N{H}_3{)}_{2}C{l}_2]$ is

• A. Square planar
• B. Pyramidal
• C. Tetrahedral
• D. Octahedral

Answer 1

Answer: (A)

O.S. of Pt (Z = 78) in the complex is + 2 $(P{t}^{2+})$
$P{t}^{2+}:[Xe{]}^{54}4f^{14}5d^8$
The eight electrons in $5d$-subshell pair up in four $d$-orbitals followed by $4s{p}^2$-hybridisation, The shape of the complex is square planar.