The frequency and intensity of a light source are doubled. Consider the following statements and judge whether it is true or false- I. Saturation photocurrent remains almost the same. II. Maximum kinetic energy of the photoelectrons is doubled.

Question

The frequency and intensity of a light source are doubled. Consider the following statements and judge whether it is true or false- I. Saturation photocurrent remains almost the same. II. Maximum kinetic energy of the photoelectrons is doubled. (A) Both I and II are true (B) I is true but II is false. (C) I is false but II is true. (D) Both I and II are false.

Tardigrade Admin · Accepted Answer

The saturation photocurrent (i) depends on intensity (

I

) of light ie,

i \propto I

.
So, when intensity changes, the saturation current also changes. Hence the statement I false.

h v = ϕ + K E_{ma x}

when

v

is doubled

K E

will change but it will be not be doubled.

Q. The frequency and intensity of a light source are doubled. Consider the following statements and judge whether it is true or false- I. Saturation photocurrent remains almost the same. II. Maximum kinetic energy of the photoelectrons is doubled.

Both I and II are true

I is true but II is false.

I is false but II is true.

Both I and II are false.

The saturation photocurrent (i) depends on intensity ( I ) of light ie, i∝I . So, when intensity changes, the saturation current also changes. Hence the statement I false. hv=ϕ+KEmax​ when v is doubled KE will change but it will be not be doubled.

Q. The frequency and intensity of a light source are doubled. Consider the following statements and judge whether it is true or false-
I. Saturation photocurrent remains almost the same.
II. Maximum kinetic energy of the photoelectrons is doubled.

The saturation photocurrent (i) depends on intensity ( $I$ ) of light ie,
$i \propto I$ .
So, when intensity changes, the saturation current also changes. Hence the statement I false.
$h v = ϕ + K E_{ma x}$
when $v$ is doubled $K E$ will change but it will be not be doubled.