The frequencies of three tuning forks A, B and C have a relation nAnBnC, When the forks A and B are sounded together the number of beats produced is n1. When A and C are sounded together the number of beats produced is n2, then the number of beats produced when B and C are sounded together is

Question

The frequencies of three tuning forks A, B and C have a relation nA>nB>nC, When the forks A and B are sounded together the number of beats produced is n1. When A and C are sounded together the number of beats produced is n2, then the number of beats produced when B and C are sounded together is (A)  n1+n2  (B)  (n1+n2/2)  (C)  n2-n1  (D)  n1-n2

Tardigrade Admin · Accepted Answer

When A and B are sounded together the number of beats =n1 When A and C are sounded together the number of beats =n2 So, the number of beats produced when B and C are sounded together =n2-n1

$n_{1} + n_{2}$

$\frac{n _{1} + n _{2}}{2}$

$n_{2} - n_{1}$

$n_{1} - n_{2}$

When A and B are sounded together the number of beats $= n_{1}$ When A and C are sounded together the number of beats $= n_{2}$ So, the number of beats produced when B and C are sounded together $= n_{2} - n_{1}$

n1​+n2​

2n1​+n2​​

n2​−n1​

n1​−n2​

When A and B are sounded together the number of beats =n1​ When A and C are sounded together the number of beats =n2​ So, the number of beats produced when B and C are sounded together =n2​−n1​

$n_{1} + n_{2}$

$\frac{n _{1} + n _{2}}{2}$

$n_{2} - n_{1}$

$n_{1} - n_{2}$

When A and B are sounded together the number of beats $= n_{1}$ When A and C are sounded together the number of beats $= n_{2}$ So, the number of beats produced when B and C are sounded together $= n_{2} - n_{1}$