The. free energy change for the decomposition reaction, (2/3)Al2O3 xrightarrow[](4/3)Al+O2 is Δ G=+960 kJ ( F=96500 text C mol-1 ) The minimum potential difference required to reduce Al2O3 at 500° C will be

Question

The. free energy change for the decomposition reaction, (2/3)Al2O3 xrightarrow[](4/3)Al+O2 is Δ G=+960 kJ ( F=96500 text C mol-1 ) The minimum potential difference required to reduce Al2O3 at 500° C will be (A) 1.345V (B) 1.724V (C) 2.146V (D) 2.487V

Tardigrade Admin · Accepted Answer

Al2O3(2Al3++3O2-) xrightarrow[]2Al+(3/2)O2; n=6e- (2/3)Al2O3 xrightarrow[](4/3)Al+O2; n=4e- Δ G=+960 kJ=+960000J Δ G=-nFE 960000=-4× 96500× E E=-2.487 V Minimum potential difference required to reduce Al2O3 is 2.487 V.

Q. The. free energy change for the decomposition reaction, 32​Al2​O3​​34​Al+O2​ is ΔG=+960kJ ( F=96500Cmol−1 ) The minimum potential difference required to reduce Al2​O3​ at 500∘C will be

1.345V

1.724V

2.146V

2.487V

Al2​O3​(2Al3++3O2−)​2Al+23​O2​; n=6e− 32​Al2​O3​​34​Al+O2​; n=4e− ΔG=+960kJ=+960000J ΔG=−nFE 960000=−4×96500×E E=−2.487V Minimum potential difference required to reduce Al2​O3​ is 2.487 V.

Q. The. free energy change for the decomposition reaction, $\frac{2}{3} A l_{2} O_{3} \frac{4}{3} A l + O_{2}$ is $Δ G = + 960 k J$ ( $F = 96500 C m o l^{- 1}$ ) The minimum potential difference required to reduce $A l_{2} O_{3}$ at $500^{\circ} C$ will be