The formation of O2+[PtF6]- is the basis for the formation of xenon fluorides. This is because

Question

The formation of O2+[PtF6]- is the basis for the formation of xenon fluorides. This is because (A)  O2 and Xe have comparable sizes (B) Both O2 and Xe are gases (C)  O2 and Xe have comparable lonisation energies (D) Both (a) and (c)

Tardigrade Admin · Accepted Answer

The first ionisation energy of xenon is quite close to that of oxygen and the molecular diameter of xenon and oxygen are almost identical. Based on the above facts it is suggested that since oxygen combines with PtF6, so xenon should also form similar compound with PtF6 .

Q. The formation of $O_{2}^{+} [Pt F_{6}]^{-}$ is the basis for the formation of xenon fluorides. This is because

$O_{2}$ and $X e$ have comparable sizes

Both $O_{2}$ and $X e$ are gases

$O_{2}$ and $X e$ have comparable lonisation energies

Both (a) and (c)

The first ionisation energy of xenon is quite close to that of oxygen and the molecular diameter of xenon and oxygen are almost identical. Based on the above facts it is suggested that since oxygen combines with $Pt F_{6},$ so xenon should also form similar compound with $Pt F_{6}$ .

Q. The formation of O2+​[PtF6​]− is the basis for the formation of xenon fluorides. This is because

O2​ and Xe have comparable sizes

Both O2​ and Xe are gases

O2​ and Xe have comparable lonisation energies