The formation of molecular complex BF3 — NH3 results in a change in hybridization of boron

Question

The formation of molecular complex BF3 — NH3 results in a change in hybridization of boron (A) from sp2 to dsp2 (B) from sp2 to sp3 (C) from sp3 to sp2 (D) from sp3 to sp3d

Tardigrade Admin · Accepted Answer

In BF3, B is sp2 hybridized with one empty pz orbital. The empty pz orbital of BF3 can be filled by lone pair of molecules such as NH3. When this occurs a tetrahedral molecule or ion is farmed which is sp3 hybridized.

Q. The formation of molecular complex $B F_{3} — N H_{3}$ results in a change in hybridization of boron

from $s p^{2}$ to $d s p^{2}$

from $s p^{2}$ to $s p^{3}$

from $s p^{3}$ to $s p^{2}$

from $s p^{3}$ to $s p^{3} d$

In $B F_{3}$ , B is $s p^{2}$ hybridized with one empty $p_{z}$ orbital. The empty $p_{z}$ orbital of $B F_{3}$ can be filled by lone pair of molecules such as $N H_{3}$ . When this occurs a tetrahedral molecule or ion is farmed which is $s p^{3}$ hybridized.

Q. The formation of molecular complex BF3​—NH3​ results in a change in hybridization of boron

from sp2 to dsp2

from sp2 to sp3

from sp3 to sp2

from sp3 to sp3d