The final molarity of a solution made by mixing 50 mL of 0.5 M HCl, 150 mL of 0.25 M HCl and water to make the volume 250 mL is

Question

The final molarity of a solution made by mixing 50 mL of 0.5 M HCl, 150 mL of 0.25 M HCl and water to make the volume 250 mL is (A) 0.5 M (B) 1 M (C) 0.75 M (D) 0.25 M

Tardigrade Admin · Accepted Answer

M1V1 +M2V2 = MV 0.5×50+0.25×150 = M×250 M=( 25+37.5/250) = 0.25M

Q. The final molarity of a solution made by mixing $50 m L$ of $0.5 M H Cl, 150 m L$ of $0.25 M H Cl$ and water to make the volume $250 m L$ is

$0.5 M$

$1 M$

$0.75 M$

$0.25 M$

$M_{1} V_{1} + M_{2} V_{2} = M V$
$0.5 \times 50 + 0.25 \times 150 = M \times 250$
$M = \frac{25 + 37.5}{250} = 0.25 M$

Q. The final molarity of a solution made by mixing 50mL of 0.5MHCl,150mL of 0.25MHCl and water to make the volume 250mL is

0.5M

1M

0.75M

0.25M