The expression for equilibrium constant, Kc for the following reaction is 2Cu(NO3)2(s) leftharpoons 2CuO(s) +4NO2(g) +O2(g)

Question

The expression for equilibrium constant, Kc for the following reaction is 2Cu(NO3)2(s) leftharpoons 2CuO(s) +4NO2(g) +O2(g) (A) Kc=([CuO(s)]2[NO2(g)]4[O2(g)]/[Cu(NO3)2(s)]2) (B) Kc=([NO2(g)]4[O2(g)]/[Cu(NO3)2(s)]2) (C) Kc=[NO2(g)]4[O2(g)] (D) Kc=([CuO(s)]2/[Cu(NO3)2(s)]2)

Tardigrade Admin · Accepted Answer

2Cu(NO3)2(s) leftharpoons 2CuO(s) +4NO2(g) +O2(g) Since conc, of solids is taken as 1, the expression for Kc becomes Kc=[NO2(g)]4[O2(g)]

Q. The expression for equilibrium constant, $K_{c}$ for the following reaction is
$2 C u (N O_{3})_{2 (s)} ⇌ 2 C u O_{(s)} + 4 N O_{2 (g)} + O_{2 (g)}$

$K_{c} = \frac{[ C u O _{(s)} ] ^{2} [ N O _{2 (g)} ] ^{4} [ O _{2 (g)} ]}{[ C u ( N O _{3} ) _{2 (s)} ] ^{2}}$

$K_{c} = \frac{[ N O _{2 (g)} ] ^{4} [ O _{2 (g)} ]}{[ C u ( N O _{3} ) _{2 (s)} ] ^{2}}$

$K_{c} = [N O_{2 (g)}]^{4} [O_{2 (g)}]$

$K_{c} = \frac{[ C u O _{(s)} ] ^{2}}{[ C u ( N O _{3} ) _{2 (s)} ] ^{2}}$

$2 C u (N O_{3})_{2 (s)} ⇌ 2 C u O_{(s)} + 4 N O_{2 (g)} + O_{2 (g)}$
Since conc, of solids is taken as $1$ , the expression for $K_{c}$ becomes
$K_{c} = [N O_{2 (g)}]^{4} [O_{2 (g)}]$

Q. The expression for equilibrium constant, Kc​ for the following reaction is 2Cu(NO3​)2(s)​⇌2CuO(s)​+4NO2(g)​+O2(g)​

Kc​=[Cu(NO3​)2(s)​]2[CuO(s)​]2[NO2(g)​]4[O2(g)​]​

Kc​=[Cu(NO3​)2(s)​]2[NO2(g)​]4[O2(g)​]​

Kc​=[NO2(g)​]4[O2(g)​]

Kc​=[Cu(NO3​)2(s)​]2[CuO(s)​]2​