Question

The expression $\frac{1+3+5+\dots +99}{2+4+6+\dots .+100}$ when simplified, reduces to the fraction

• A. $\frac{49}{50}$
• B. $\frac{50}{51}$
• C. $\frac{99}{100}$
• D. $\frac{100}{101}$

Answer 1

Answer: (B)

$S_N=50^2;S_D=\frac{2\cdot 50\cdot 51}{2}=50\cdot 51$
$\Rightarrow \frac{N}{D}=\frac{50}{51}$