The excess pressure inside a spherical drop of water is four times that of another drop. Then, their respective mass ratio is

Question

The excess pressure inside a spherical drop of water is four times that of another drop. Then, their respective mass ratio is (A) 1:16 (B) 8:1 (C) 1:4 (D) 1:64

Tardigrade Admin · Accepted Answer

Excess pressure inside a spherical drop of water p=(2 T/R) Given, p1=4p2 (2 T/R1)=4× (2 T/R2 ) or R2=4R1 Now, (m1/m2)=(4 π R13 d1/4 π R23 d2) or (m1/m2)=(R13/R23) (m1/m2 )=(1/64)

Q. The excess pressure inside a spherical drop of water is four times that of another drop. Then, their respective mass ratio is

$1 : 16$

$8 : 1$

$1 : 4$

$1 : 64$

Q. The excess pressure inside a spherical drop of water is four times that of another drop. Then, their respective mass ratio is

1:16

8:1

1:4

1:64

Excess pressure inside a spherical drop of water p=R2T​ Given,p1​=4p2​ R1​2T​=4×R2​2T​ orR2​=4R1​ Now,m2​m1​​=4πR23​d2​4πR13​d1​​ orm2​m1​​=R23​R13​​ m2​m1​​=641​

$1 : 16$

$8 : 1$

$1 : 4$

$1 : 64$