The equivalent weight of a metal is 4.5 and the molecular weight of its chloride is 80 . The atomic weight of the metal is

Question

The equivalent weight of a metal is 4.5 and the molecular weight of its chloride is 80 . The atomic weight of the metal is (A) 18 (B) 9 (C) 4.5 (D) 36

Tardigrade Admin · Accepted Answer

Let metal chloride is M Cl x (Suppose metal is x valent), then molecular weight of M Cl x = Equivalent weight of metal × x+x × 35.5=80 4.5 x+35.5 x=80 ⇒ ∴ x=2 ∴ Atomic weight of metal =4.5 × 2=9

Q. The equivalent weight of a metal is $4.5$ and the molecular weight of its chloride is $80$ . The atomic weight of the metal is

18

9

4.5

36

Let metal chloride is $MC l_{x}$ (Suppose metal is $x$ valent), then molecular weight of $MC l_{x}$

$=$ Equivalent weight of metal $\times x + x \times 35.5 = 80$

$4.5 x + 35.5 x = 80$

$\Rightarrow ∴ x = 2$

$∴$ Atomic weight of metal $= 4.5 \times 2 = 9$

Q. The equivalent weight of a metal is 4.5 and the molecular weight of its chloride is 80 . The atomic weight of the metal is

18

9

4.5

36

Let metal chloride is MClx​ (Suppose metal is x valent), then molecular weight of MClx​ = Equivalent weight of metal ×x+x×35.5=80 4.5x+35.5x=80 ⇒∴x=2 ∴ Atomic weight of metal =4.5×2=9

Q. The equivalent weight of a metal is $4.5$ and the molecular weight of its chloride is $80$ . The atomic weight of the metal is

Let metal chloride is $MC l_{x}$ (Suppose metal is $x$ valent), then molecular weight of $MC l_{x}$

$=$ Equivalent weight of metal $\times x + x \times 35.5 = 80$

$4.5 x + 35.5 x = 80$

$\Rightarrow ∴ x = 2$

$∴$ Atomic weight of metal $= 4.5 \times 2 = 9$