The equivalent conductance of M / 32 solution of a weak monobasic acid is 8.0 mho cm 2 and at infinite dilution is 400 mh ° cm 2. The dissociation constant of this acid is

Question

The equivalent conductance of M / 32 solution of a weak monobasic acid is 8.0 mho cm 2 and at infinite dilution is 400 mh ° cm 2. The dissociation constant of this acid is (A) 1.25 × 10-6 (B) 6.25 × 10-4 (C) 1.25 × 10-4 (D) 1.25 × 10-5

Tardigrade Admin · Accepted Answer

α=(∧ e q/∧e q0)=(8/400) ⇒ 2 × 10-2 k=c α2=(1/32) ×(2 × 10-2)2 =(4/32) × 10-4=1.25 × 10-5

Q. The equivalent conductance of $M /32$ solution of a weak monobasic acid is $8.0 mh o c m^{2}$ and at infinite dilution is $400 mh \circ c m^{2}$ . The dissociation constant of this acid is

$1.25 \times 1 0^{- 6}$

$6.25 \times 1 0^{- 4}$

$1.25 \times 1 0^{- 4}$

$1.25 \times 1 0^{- 5}$

$α = \frac{\land e q}{\land _{e q}^{0}} = \frac{8}{400}$
$\Rightarrow 2 \times 1 0^{- 2}$
$k = c α^{2} = \frac{1}{32} \times (2 \times 1 0^{- 2})^{2}$
$= \frac{4}{32} \times 1 0^{- 4} = 1.25 \times 1 0^{- 5}$

Q. The equivalent conductance of M/32 solution of a weak monobasic acid is 8.0mhocm2 and at infinite dilution is 400mh∘cm2. The dissociation constant of this acid is

1.25×10−6

6.25×10−4

1.25×10−4

1.25×10−5