Question

The equivalent capacitance between A and B is,

• A. 150 pF
• B. 50 pF
• C. 300 pF
• D. $\frac{100}{3}pF$

Answer 1

Answer: (D)

$C_{AB}=\left(50||50\right)series50=\frac{100\times 50}{100+50}=\frac{100}{3}pF$