Question

The equivalent capacitance between a and b for the combination of capacitors shown in figure where all capacitances are in microfarad is

• A. $6.0\mu F$
• B. $4.0\mu F$
• C. $2.0\mu F$
• D. $3.0\mu F$

Answer 1

Answer: (A)

Rearranging the circuits, we get the following circuit

$\therefore$ equivalent capacitance between $A$ and $B$
$C_{AB}=\frac{4\times 4}{4+4}=2\mu F$
and equivalent capacitance between $C$ and $A$
$C_{CD}=\frac{8\times 8}{8+8}=4\mu F$
$\therefore C_{ab}=2\mu F+4\mu F=6\mu F$