The equilibrium constant of the reaction: Cu ( s )+2 Ag +( aq ) arrow Cu 2+( aq )+2 Ag ( s ) E° =0.46 V at 298 K is:

Question

The equilibrium constant of the reaction: Cu ( s )+2 Ag +( aq ) arrow Cu 2+( aq )+2 Ag ( s ) E° =0.46 V at 298 K is: (A) 2.0 × 1010  (B) 4.0 × 1010  (C) 4.0 × 1015  (D) 2.4 × 1010

Tardigrade Admin · Accepted Answer

Cu(s)+2 Ag2+(aq) arrow Cu2+(aq)+2 Ag(s) E0=0.46 V at 298 K R T textIn K=n F E0 In K=(n F E0/R T) In K=(2 × 0.46/0.0591) K=4 × 1015

Q. The equilibrium constant of the reaction:
$C u (s) + 2 A g^{+} (a q) \to C u^{2 +} (a q) + 2 A g (s)$
$E^{\circ} = 0.46 V$ at $298 K$ is:

$2.0 \times 1 0^{10}$

$4.0 \times 1 0^{10}$

$4.0 \times 1 0^{15}$

$2.4 \times 1 0^{10}$

$C u (s) + 2 A g^{2 +} (a q) \to C u^{2 +} (a q) + 2 A g (s)$
$E^{0} = 0.46 V$ at $298 K$
$RT In K = n F E^{0}$
In $K = \frac{n F E ^{0}}{RT}$
In $K = \frac{2 \times 0.46}{0.0591}$
$K = 4 \times 1 0^{15}$

Q. The equilibrium constant of the reaction: Cu(s)+2Ag+(aq)→Cu2+(aq)+2Ag(s) E∘=0.46V at 298K is:

2.0×1010

4.0×1010

4.0×1015

2.4×1010