The equilibrium constant for the reaction, A( g )+B( g ) leftharpoons 2 C( g ) is 3 × 10-4 at 500 K. In the presence of a catalyst the equilibrium is attained 10 times faster. The equilibrium constant in the presence of a catalyst at 500 K has the value:

Question

The equilibrium constant for the reaction, A( g )+B( g ) leftharpoons 2 C( g ) is 3 × 10-4 at 500 K. In the presence of a catalyst the equilibrium is attained 10 times faster. The equilibrium constant in the presence of a catalyst at 500 K has the value: (A) 3 × 10-4 (B) 30 × 10-4 (C) 3 × 10-3 (D) 0.3 × 10-3

Tardigrade Admin · Accepted Answer

Correct answer is (a) 3 × 10-4Correct answer is (d) 0.3 × 10-3

Q. The equilibrium constant for the reaction, $A (g) + B (g) ⇌ 2 C (g)$ is $3 \times 1 0^{- 4}$ at $500 K$ . In the presence of a catalyst the equilibrium is attained $10$ times faster. The equilibrium constant in the presence of a catalyst at $500 K$ has the value:

$3 \times 1 0^{- 4}$

$30 \times 1 0^{- 4}$

$3 \times 1 0^{- 3}$

$0.3 \times 1 0^{- 3}$

Correct answer is (a) $3 \times 1 0^{- 4}$ Correct answer is (d) $0.3 \times 1 0^{- 3}$

Q. The equilibrium constant for the reaction, A(g)+B(g)⇌2C(g) is 3×10−4 at 500K. In the presence of a catalyst the equilibrium is attained 10 times faster. The equilibrium constant in the presence of a catalyst at 500K has the value:

3×10−4

30×10−4

3×10−3

0.3×10−3