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Complex Numbers and Quadratic Equations
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Solution:
∣z+1−i∣=∣z−1+i∣ ⇒∣z−(−1+i)∣=∣z−(1−i)∣ ⇒PA=PB, where A denotes the point (−1,1),B denotes the point (1,−1) and P denotes the point (x,y). ⇒z lies on the perpendicular bisector of the line joining A and B and perpendicular bisector is a straight line.