Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The equation of the normal to the circle x2+y2=9 at the point ((3/√2), (3/√2)) is -
Q. The equation of the normal to the circle
x
2
+
y
2
=
9
at the point
(
2
3
,
2
3
)
is -
102
186
Conic Sections
Report Error
A
x
−
y
=
3
2
B
x
+
y
=
0
C
x
−
y
=
0
D
none of these
Solution:
Correct answer is (c)
x
−
y
=
0