The entropy values (in JK-1mol-1 ) of H2(g)=130.6, text Cl2(g)=223.0 and HCl(g)= 186.7 at 298 K and 1 atm pressure. Then entropy change for the reaction. H2(g)+Cl2(g) xrightarrow[]2HCl(g) is:

Question

The entropy values (in JK-1mol-1 ) of H2(g)=130.6, text Cl2(g)=223.0 and HCl(g)= 186.7 at 298 K and 1 atm pressure. Then entropy change for the reaction. H2(g)+Cl2(g) xrightarrow[]2HCl(g) is: (A) 540.3 (B) 727.3 (C)  -166.9  (D) 19.8

Tardigrade Admin · Accepted Answer

Δ S=Sp-SR H2(g)+Cl2(g) xrightarrow[]2HCl(g) Given SoH(g)=130.6JK-1/mol SoCl2(g)=223.0 text JK-1/mol SoHCl(g)=186.7 text JK-1/mol Δ S=2SoHCl-(SoH2+SoCl2) =2× 186.7-(130.6+223.0) =373.4-353.6=19.8 text JK-1mol-1

Q. The entropy values (in $J K^{- 1} m o l^{- 1}$ ) of $H_{2} (g) = 130.6, C l_{2} (g) = 223.0$ and $H Cl (g) =$ $186.7$ at $298 K$ and 1 atm pressure. Then entropy change for the reaction. $H_{2} (g) + C l_{2} (g) 2 H Cl (g)$ is:

540.3

727.3

$- 166.9$

19.8

Q. The entropy values (in JK−1mol−1 ) of H2​(g)=130.6,Cl2​(g)=223.0 and HCl(g)= 186.7 at 298K and 1 atm pressure. Then entropy change for the reaction. H2​(g)+Cl2​(g)​2HCl(g) is:

540.3

727.3

−166.9

19.8

ΔS=Sp​−SR​ H2​(g)+Cl2​(g)​2HCl(g) Given SoH(g)=130.6JK−1/mol SoCl2​(g)=223.0JK−1/mol SoHCl(g)=186.7JK−1/mol ΔS=2SoHCl−(SoH2​+SoCl2​) =2×186.7−(130.6+223.0) =373.4−353.6=19.8JK−1mol−1

Q. The entropy values (in $J K^{- 1} m o l^{- 1}$ ) of $H_{2} (g) = 130.6, C l_{2} (g) = 223.0$ and $H Cl (g) =$ $186.7$ at $298 K$ and 1 atm pressure. Then entropy change for the reaction. $H_{2} (g) + C l_{2} (g) 2 H Cl (g)$ is:

$- 166.9$