The enthalpy of neutralization of NH4OH and CH3COOH is -10.5 kcal mol- 1 and enthalpy of neutralisation of NH4OH with a strong acid is -11.7 kcal mol- 1 . The enthalpy of ionization of CH3COOH will be

Question

The enthalpy of neutralization of NH4OH and CH3COOH is -10.5 kcal mol- 1 ​ and enthalpy of neutralisation of NH4OH with a strong acid is -11.7 kcal mol- 1 . The enthalpy of ionization of CH3COOH will be (A) 4.0 kcal mol- 1 (B) 3.0 kcal mol- 1 (C) 1.2 kcal mol- 1 (D) 3.2 kcal mol- 1

Tardigrade Admin · Accepted Answer

Enthalpy of neutralisation is the amount of energy released during the combination of one moe strong monobasic acid neutralised with the one-mole strong monoacidic base.

H^{+} (a q) + (O H)^{-} (a q) \to H_{2} O (l) (Δ)_{neut.} H = - 13.7 k c a l

Enthalpy of ionisation of

C H_{3} COO H & N H_{4} O H

together

= - 10.5 - (- 13.7) = + 3.2 Kc a l

Enthalpy of ionisation of only

N H_{4} O H = - 11.7 - (- 13.7) = + 2 Kc a l

Enthalpy of ionisation of only

C H_{3} COO H = 3.2 - 2 = 1.2 Kc a l

Q. The enthalpy of neutralization of $N H_{4} O H$ and $C H_{3} COO H$ is $- 10.5 k c a l m o l^{- 1}$ and enthalpy of neutralisation of $N H_{4} O H$ with a strong acid is $- 11.7 k c a l m o l^{- 1}$ . The enthalpy of ionization of $C H_{3} COO H$ will be

$4.0 k c a l m o l^{- 1}$

$3.0 k c a l m o l^{- 1}$

$1.2 k c a l m o l^{- 1}$

$3.2 k c a l m o l^{- 1}$

Q. The enthalpy of neutralization of NH4​OH and CH3​COOH is −10.5kcalmol−1 ​ and enthalpy of neutralisation of NH4​OH with a strong acid is −11.7kcalmol−1 . The enthalpy of ionization of CH3​COOH will be

4.0kcalmol−1

3.0kcalmol−1

1.2kcalmol−1

3.2kcalmol−1

Q. The enthalpy of neutralization of $N H_{4} O H$ and $C H_{3} COO H$ is $- 10.5 k c a l m o l^{- 1}$ and enthalpy of neutralisation of $N H_{4} O H$ with a strong acid is $- 11.7 k c a l m o l^{- 1}$ . The enthalpy of ionization of $C H_{3} COO H$ will be

$4.0 k c a l m o l^{- 1}$

$3.0 k c a l m o l^{- 1}$

$1.2 k c a l m o l^{- 1}$

$3.2 k c a l m o l^{- 1}$