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Chemistry
The enthalpies of combustion of S (s), SO 2(g) and H 2(g) are -298.2,-98.7 and -287.3 kJ mol -1. If the enthalpy of reaction SO 3(g)+ H 2 O (l) arrow H 2 SO 4(l) is -130.2 kJ mol -1, the enthalpy of formation of H 2 SO 4(l) would be
Q. The enthalpies of combustion of
S
(
s
)
,
S
O
2
(
g
)
and
H
2
(
g
)
are -298.2,-98.7 and
−
287.3
k
J
m
o
l
−
1
. If the enthalpy of reaction
S
O
3
(
g
)
+
H
2
O
(
l
)
→
H
2
S
O
4
(
l
)
is
−
130.2
k
J
m
o
l
−
1
,
the enthalpy of formation of
H
2
S
O
4
(
l
)
would be
2163
216
Thermodynamics
Report Error
A
−
814.4
k
J
m
o
l
−
1
47%
B
−
650.3
k
J
m
o
l
−
1
7%
C
−
554.2
k
J
m
o
l
−
1
34%
D
−
435.5
k
J
m
o
l
−
1
12%
Solution:
S
+
O
2
→
S
O
2
;
Δ
H
=
−
298.2
k
J
m
o
l
−
1
S
O
2
+
2
1
O
2
→
S
O
3
;
Δ
H
=
−
98.7
k
J
m
o
l
−
1
H
2
+
2
1
O
2
→
H
2
O
;
Δ
H
=
−
287.3
k
J
m
o
l
−
1
and
S
O
3
+
H
2
O
→
H
2
S
O
4
;
Δ
H
=
−
130.2
k
J
m
o
l
−
1
.
Formation of
H
2
S
O
4
implies
H
2
(
g
)
+
S
(
s
)
+
2
O
2
(
g
)
→
H
2
S
O
4
(
l
)
and this reaction can be
obtained by adding the given four reactions.
∴
Δ
H
=
−
298.2
+
(
−
98.7
)
+
(
−
287.3
)
+
(
−
130.2
)
=
−
814.4
k
J
m
o
l
−
1