The energy of photon is given as: Δ e / atom =3.03 × 10-19 J atom -1, then the wavelength (λ) of the photon is (Given, h(. Planck's constant) =6,63 × 10-34 Js, c (velocity of light) =3.00 × 108 ms -1 )

Question

The energy of photon is given as: Δ e / atom =3.03 × 10-19 J atom -1, then the wavelength (λ) of the photon is (Given, h(. Planck's constant) =6,63 × 10-34 Js, c (velocity of light) =3.00 × 108 ms -1 ) (A) 6.56 nm (B) 65.7 nm (C) 656 nm (D) 0.656 nm

Tardigrade Admin · Accepted Answer

According to formula,E=(h c/λ)(v=(c/λ)) Energy E=h v 3.03 × 10-19=(h c/λ) λ=(6.63 × 10-34 × 3.0 × 108/3.03 × 10-19) =6.56 × 10-7 m =6.56 × 10-7 × 109 nm =6.56 × 102 nm =656 nm

Q. The energy of photon is given as : Δe/ atom =3.03×10−19Jatom−1, then the wavelength (λ) of the photon is (Given, h( Planck's constant) =6,63×10−34Js,c (velocity of light) =3.00×108ms−1 )

6.56 nm

65.7 nm

656 nm

0.656 nm

According to formula,E=λhc​(v=λc​) Energy E=hv 3.03×10−19=λhc​ λ=3.03×10−196.63×10−34×3.0×108​ =6.56×10−7m =6.56×10−7×109nm =6.56×102nm=656nm

Q. The energy of photon is given as :
$Δ e /$ atom $= 3.03 \times 1 0^{- 19} J a t o m^{- 1}$ , then the wavelength $(λ)$ of the photon is
(Given, $h ($ Planck's constant) $= 6, 63 \times 1 0^{- 34} J s, c$ (velocity of light) $= 3.00 \times 1 0^{8} m s^{- 1}$ )