The energy of one mole of photons of radiation of wavelength 300 nm is (Given: h =6.63 × 10-34 Js , N A =6.02 × 1023 mol -1, c =3 × 108 ms -1 )

Question

The energy of one mole of photons of radiation of wavelength 300 nm is (Given: h =6.63 × 10-34 Js , N A =6.02 × 1023 mol -1, c =3 × 108 ms -1 ) (A) 235 kJ mol -1 (B) 325 kJ mol -1 (C) 399 kJ mol -1 (D) 435 kJ mol -1

Tardigrade Admin · Accepted Answer

Energy of one mole of photons =( hc /λ) × N A =(6.63 × 10-34 × 3 × 108/300 × 10-9) × 6.02 × 1023 =399.13 × 103 Joule / mole =399 kJ / mole

Q. The energy of one mole of photons of radiation of wavelength $300 nm$ is
(Given : $h = 6.63 \times 1 0^{- 34} J s, N_{A} = 6.02 \times 1 0^{23} m o l^{- 1}$ , $c = 3 \times 1 0^{8} m s^{- 1}$ )

$235 k J m o l^{- 1}$

$325 k J m o l^{- 1}$

$399 k J m o l^{- 1}$

$435 k J m o l^{- 1}$

Energy of one mole of photons $= \frac{h c}{λ} \times N_{A}$
$= \frac{6.63 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{300 \times 1 0 ^{- 9}} \times 6.02 \times 1 0^{23}$
$= 399.13 \times 1 0^{3}$ Joule / mole
$= 399$ kJ / mole

Q. The energy of one mole of photons of radiation of wavelength 300nm is (Given : h=6.63×10−34Js,NA​=6.02×1023mol−1, c=3×108ms−1 )

235kJmol−1

325kJmol−1

399kJmol−1

435kJmol−1