The energy of an electron in the first orbit of the hydrogen atom is -2.18× 10- 18 J/atom . What is the third ionisation energy of Li2 + ion?

Question

The energy of an electron in the first orbit of the hydrogen atom is -2.18× 10- 18 J/atom . What is the third ionisation energy of Li2 + ion? (A) 8.72× 10- 18J (B) 4.36× 10- 18J (C) +19.62× 10- 18J (D) 6.54× 10- 18J

Tardigrade Admin · Accepted Answer

IlI. Ionisation energy of Li +2 =-( z 2/ n 2) E 1 H ( z =3, n =1) =-( z 2 ×-2.18 × 10-18/ n 2) J / species =--9 × 2.18 × 10-18 =19.62 × 10-18 J

Q. The energy of an electron in the first orbit of the hydrogen atom is $- 2.18 \times 1 0^{- 18} J / a t o m$ . What is the third ionisation energy of $L i^{2 +}$ ion?

$8.72 \times 1 0^{- 18} J$

$4.36 \times 1 0^{- 18} J$

$+ 19.62 \times 1 0^{- 18} J$

$6.54 \times 1 0^{- 18} J$

IlI. Ionisation energy of $L i^{+ 2}$
$= - \frac{z ^{2}}{n ^{2}} E_{1} H (z = 3, n = 1)$
$= - \frac{z ^{2} \times- 2.18 \times 1 0 ^{- 18}}{n ^{2}} J /$ species
$= - - 9 \times 2.18 \times 1 0^{- 18}$
$= 19.62 \times 1 0^{- 18} J$

Q. The energy of an electron in the first orbit of the hydrogen atom is −2.18×10−18J/atom . What is the third ionisation energy of Li2+ ion?

8.72×10−18J

4.36×10−18J

+19.62×10−18J

6.54×10−18J