The energy of a photon of wavelength (λ) = 1 m is (Planck’s constant = 6.626× 10-34 Js , speed of light = 3 × 108ms-2)

Question

The energy of a photon of wavelength (λ) = 1 m is (Planck’s constant = 6.626× 10-34 Js , speed of light = 3 × 108ms-2) (A) 1.988 × 10-23J (B) 1.988 × 10-28J (C) 1.988 × 10-30J (D) 1.988 × 10-25J

Tardigrade Admin · Accepted Answer

Given, wavelength of photon = 1 m Speed of light = 3 ×108 ms-1 Energy of photon =(hc/λ) Substituting the values in above equation we get, E=(6.626×10-34 Js×3×108 ms-1/1 m) =1.988×10-23 J

Q. The energy of a photon of wavelength $(λ) = 1 m$ is (Planck’s constant $= 6.626 \times 1 0^{- 34} J s$ , speed of light $= 3 \times 1 0^{8} m s^{- 2}$ )

$1.988 \times 1 0^{- 23} J$

$1.988 \times 1 0^{- 28} J$

$1.988 \times 1 0^{- 30} J$

$1.988 \times 1 0^{- 25} J$

Given, wavelength of photon $= 1 m$
Speed of light $= 3 \times 1 0^{8} m s^{- 1}$
Energy of photon $= \frac{h c}{λ}$
Substituting the values in above equation
we get, $E = \frac{6.626 \times 1 0 ^{- 34} J s \times 3 \times 1 0 ^{8} m s ^{- 1}}{1 m}$
$= 1.988 \times 1 0^{- 23} J$

Q. The energy of a photon of wavelength (λ)=1m is (Planck’s constant =6.626×10−34Js , speed of light =3×108ms−2)

1.988×10−23J

1.988×10−28J

1.988×10−30J

1.988×10−25J