The energy difference between the first two levels of hydrogen atom is 10.2eV. For another element of atomic number 10 and mass number 20, this will be

Question

The energy difference between the first two levels of hydrogen atom is 10.2eV. For another element of atomic number 10 and mass number 20, this will be (A) 1020 eV (B) 2040 eV (C) 0.51 eV (D) 0.102 eV

Tardigrade Admin · Accepted Answer

For hydrogen atom, energy difference Δ EH=R h c((1/n12)-(1/n22)) For other atoms, Δ E'Z2 R h c((1/n12)-(1/n22))=Z2 Δ EH =(10)2 × 10.2 =1020 eV

Q. The energy difference between the first two levels of hydrogen atom is 10.2eV. For another element of atomic number 10 and mass number 20, this will be

1020 eV

2040 eV

0.51 eV

0.102 eV

For hydrogen atom, energy difference
$Δ E_{H} = R h c (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}})$
For other atoms,
$Δ E^{'} Z^{2} R h c (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}}) = Z^{2} Δ E_{H}$
$= (10)^{2} \times 10.2$
$= 1020 e V$

Q. The energy difference between the first two levels of hydrogen atom is 10.2eV. For another element of atomic number 10 and mass number 20, this will be

1020 eV

2040 eV

0.51 eV

0.102 eV

For hydrogen atom, energy difference ΔEH​=Rhc(n12​1​−n22​1​) For other atoms, ΔE′Z2Rhc(n12​1​−n22​1​)=Z2ΔEH​ =(10)2×10.2 =1020eV

For hydrogen atom, energy difference
$Δ E_{H} = R h c (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}})$
For other atoms,
$Δ E^{'} Z^{2} R h c (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}}) = Z^{2} Δ E_{H}$
$= (10)^{2} \times 10.2$
$= 1020 e V$