The end product in the sequence would be C3H7OH xrightarrow[170o]H2SO4A xrightarrowBr2B xrightarrow[KOH]Alc.C

Question

The end product in the sequence would be C3H7OH xrightarrow[170o]H2SO4A xrightarrowBr2B xrightarrow[KOH]Alc.C  (A)  CH3C≡ CH  (B)  CH3 text underset beginsmallmatrix | OH endsmallmatrix mathopC =CH2  (C)  CH2=C=CH2  (D)  CH3 text underset beginsmallmatrix | OH endsmallmatrix mathopCH - underset beginsmallmatrix | OH endsmallmatrix mathopCH2

Tardigrade Admin · Accepted Answer

CH3CH2CH2OH xrightarrow[ beginsmallmatrix 170o (dehydration) endsmallmatrix]H2SO4 underset beginsmallmatrix propene 'A' endsmallmatrix mathopCH3CH=CH2 xrightarrowBr2 underset1, text 2-dibromopropane mathop overset beginsmallmatrix Br | endsmallmatrix mathopCH3CH - underset beginsmallmatrix | Br endsmallmatrix mathopCH2 xrightarrow[(Dehydrohalogenation)]Alc. KOH underset beginsmallmatrix propyne 'C' endsmallmatrix mathopCH3C≡ CH

Q. The end product in the sequence would be $C_{3} H_{7} O H H_{2} S O_{4} 170^{o} A B r_{2} B A l c . K O H C$

$C H_{3} C \equiv C H$

$C H_{3} ∣ O H C = C H_{2}$

$C H_{2} = C = C H_{2}$

$C H_{3} ∣ O H C H - ∣ O H C H_{2}$

$C H_{3} C H_{2} C H_{2} O H H_{2} S O_{4} 170^{o} (d e h y d r a t i o n) p ro p e n e^{'} A^{'} C H_{3} C H = C H_{2}$ $B r_{2} 1, 2 - d ib ro m o p ro p an e C H_{3} C H B r ∣ - ∣ B r C H_{2} A l c . K O H (De h y d ro ha l o g e na t i o n)$ $p ro p y n e^{'} C^{'} C H_{3} C \equiv C H$

Q. The end product in the sequence would be C3​H7​OHH2​SO4​170o​ABr2​​BAlc.KOH​C

CH3​C≡CH

CH3​∣OH​C​=CH2​

CH2​=C=CH2​

CH3​∣OH​CH​−∣OH​CH2​​