The empirical formula of a non-electrolyte is CH2O. A solution containing 6 g of the compound exerts the same osmotic pressure as that of 0.05 M glucose solution at the same temperature. The molecular formula of the compound is

Question

The empirical formula of a non-electrolyte is CH2O. A solution containing 6 g of the compound exerts the same osmotic pressure as that of 0.05 M glucose solution at the same temperature. The molecular formula of the compound is (A) CH 2 O (B) C 2 H4 O 2 (C) C4H8O4 (D) C3H6O3

Tardigrade Admin · Accepted Answer

Solutions having same osmotic pressure, at a given temperature, have same concentration.
Concentration of compound = concentration of glucose

< b r / > < b r / > \frac{6}{M \times 1} = 0.05 < b r / > M = \frac{6}{0.05} = 120 < b r / > (C H_{2} O) = 12 + 2 + 16 = 30 < b r / > n = \frac{molecular mass}{empirical formula mass} = \frac{120}{30} = 4 < b r / > < b r / >

Hence, Molecular formula

(C H_{2} O)_{4} = C_{4} H_{8} O_{4}

Q. The empirical formula of a non-electrolyte is $C H_{2} O$ . A solution containing $6 g$ of the compound exerts the same osmotic pressure as that of $0.05 M$ glucose solution at the same temperature. The molecular formula of the compound is

$C H_{2} O$

$C_{2} H_{4} O_{2}$

$C_{4} H_{8} O_{4}$

$C_{3} H_{6} O_{3}$

Q. The empirical formula of a non-electrolyte is CH2​O. A solution containing 6g of the compound exerts the same osmotic pressure as that of 0.05M glucose solution at the same temperature. The molecular formula of the compound is

CH2​O

C2​H4​O2​

C4​H8​O4​

C3​H6​O3​

Q. The empirical formula of a non-electrolyte is $C H_{2} O$ . A solution containing $6 g$ of the compound exerts the same osmotic pressure as that of $0.05 M$ glucose solution at the same temperature. The molecular formula of the compound is

$C H_{2} O$

$C_{2} H_{4} O_{2}$

$C_{4} H_{8} O_{4}$

$C_{3} H_{6} O_{3}$