The empirical formula of a compound is CH 2. One mole of this compound has a mass of 42 g. Its molecular formula is :

Question

The empirical formula of a compound is CH 2. One mole of this compound has a mass of 42 g. Its molecular formula is : (A) C3H6 (B) C3H8 (C)  CH2 (D) C2H2

Tardigrade Admin · Accepted Answer

Weight of empirical formula CH 2 =12+(1 × 2) 4=12+2 =14 Mass of one mole of the compound = its molecular weight =42 n=( text Mol. wt. / text Empirical formula wt.)=(42/14)=3 ∴ Mol. formula =( Empirical formula) × n =( CH 2) × 3= C 3 H 6

Q. The empirical formula of a compound is $C H_{2}$ . One mole of this compound has a mass of $42 g$ . Its molecular formula is :

$C_{3} H_{6}$

$C_{3} H_{8}$

$C H_{2}$

$C_{2} H_{2}$

Weight of empirical formula
$C H_{2} = 12 + (1 \times 2)$
$4 = 12 + 2$
$= 14$
Mass of one mole of the compound = its molecular weight $= 42$
$n = \frac{Mol. wt.}{Empirical formula wt.} = \frac{42}{14} = 3$
$∴$ Mol. formula =( Empirical formula) $\times n$
$= (C H_{2}) \times 3 = C_{3} H_{6}$

Q. The empirical formula of a compound is CH2​. One mole of this compound has a mass of 42g. Its molecular formula is :

C3​H6​

C3​H8​

CH2​

C2​H2​