The electrophile involved in the above reaction is:

Question

The electrophile involved in the above reaction is: (A) dichloromethyl cation ( HCl 2)( C )°ledR (B) dichlorocarbene (: CCl2) (C) trichloromethyl anion (C-Cl3) (D) formyl cation (C°ledR H O)

Tardigrade Admin · Accepted Answer

CHCl3 + OH°ledR → °ledRCCl3 + H2O °ledRCCl3 :CCl3 + Cl-

Q. The electrophile involved in the above reaction is:

dichloromethyl cation $(H C l_{2}) (C)^{®}$

dichlorocarbene $(: CC l_{2})$

trichloromethyl anion $(C^{-} C l_{3})$

formyl cation $(C^{®} H O)$

$C H C l_{3} + O H^{®} \to^{®} CC l_{3} + H_{2} O$
$^{®} CC l_{3} : CC l_{3} + C l^{-}$

Q. The electrophile involved in the above reaction is:

dichloromethyl cation (HCl2​)(C)®

dichlorocarbene (:CCl2​)

trichloromethyl anion (C−Cl3​)

formyl cation (C®HO)

CHCl3​+OH®→®CCl3​+H2​O ®CCl3​:CCl3​+Cl−

dichloromethyl cation $(H C l_{2}) (C)^{®}$

dichlorocarbene $(: CC l_{2})$

trichloromethyl anion $(C^{-} C l_{3})$

formyl cation $(C^{®} H O)$

$C H C l_{3} + O H^{®} \to^{®} CC l_{3} + H_{2} O$
$^{®} CC l_{3} : CC l_{3} + C l^{-}$